再请教一道，这个题答案是A,不明白。


Q36:
What is the median number of employees assigned per project for the projects at Company Z?
(1)        25 percent of the projects at Company Z have 4 or more employees assigned to each project.
(2)        35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.
       
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

I thought it would be E. If you can assume that the number of employees assigned to each project followed certain distribution(say normal distribution), then the answer would be D.  Statement 1 and 2 are symmetric in nature, so I believe that Answer A, B, and C are not correct. Am I right?

[ 本帖最后由 userz3 于 2006-4-20 11:49 编辑 ]

1 说明75%的项目被分配了少于4个员工(不包括4)
2 说明65%的项目被分配了多于2个员工(不包括2)
这就说明至少50%以上的项目被分配了3个员工 (不能取2,4,又必须是整数,那就只有3了)
中值是指一串数排序后中间大的那个,如果一半以上的项目都被分配了3个员工, 显然中值是3

25% + 35% = 60% 的项目有三个人以上或是三个人以下，所以有 40% 的项目有三个人。把项目人数从最少到最多排列后，两个或以下员工的 35% 个项目当然在前，然后就是排有三个人的，那么到 50% 时还是在三个人的项目，所以中数是 3。

答案是 C。

明显是c啊 应该没有什么争议吧